I was exploring Jupyter notebooks , that combines live code, markdown and data, through Microsoft's implementation, known as MS Azure Notebooks , putting together a small library of R and F# notebooks . As Microsoft's FAQ for the service describes it as : ...a multi-lingual REPL on steroids. This is a free service that provides Jupyter notebooks along with supporting packages for R, Python and F# as a service. This means you can just login and get going since no installation/setup is necessary. Typical usage includes schools/instruction, giving webinars, learning languages, sharing ideas, etc. Feel free to clone and comment... In R Azure Workbook for R - Memoisation and Vectorization Charting Correlation Matrices in R In F# Charnownes Constant in FSharp.ipynb Project Euler - Problems 18 and 67 - FSharp using Dynamic Programming
I'm fairly happy with this, since it executes speedily, and builds on prior work solving problems. It uses a tail-recursive function and BigInteger to find the power, and a fairly straightforward conversion of the number in to a string, which it then sums.
Description
Solution
//tail-recursive function to sum array of BigInteger
open System.Numerics
let rec productBigInt (num:BigInteger) (power:BigInteger) (max:BigInteger) (acc:BigInteger) =
if power = max then
acc * num
else
productBigInt num (power + 1I) max (num * acc)
//smaller aspects of function ot solve problem
let prodResult = productBigInt 2I 1I 1000I 1I
let strCharProd = prodResult.ToString()
let lenProd = strCharProd.Length
//main to solve problem
let sumPower =
let prodResult = productBigInt 2I 1I 1000I 1I
let strCharProd = prodResult.ToString()
let max = strCharProd.Length
let arrNum = Array.create max 0
for i=0 to max-1 do
arrNum.[i] <- System.Convert.ToInt32(strCharProd.Chars(i).ToString())
Array.sum arrNum
Description
- 215 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.
- What is the sum of the digits of the number 2^1000?
Solution
//tail-recursive function to sum array of BigInteger
open System.Numerics
let rec productBigInt (num:BigInteger) (power:BigInteger) (max:BigInteger) (acc:BigInteger) =
if power = max then
acc * num
else
productBigInt num (power + 1I) max (num * acc)
//smaller aspects of function ot solve problem
let prodResult = productBigInt 2I 1I 1000I 1I
let strCharProd = prodResult.ToString()
let lenProd = strCharProd.Length
//main to solve problem
let sumPower =
let prodResult = productBigInt 2I 1I 1000I 1I
let strCharProd = prodResult.ToString()
let max = strCharProd.Length
let arrNum = Array.create max 0
for i=0 to max-1 do
arrNum.[i] <- System.Convert.ToInt32(strCharProd.Chars(i).ToString())
Array.sum arrNum
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